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15x^2-75x-315=0
a = 15; b = -75; c = -315;
Δ = b2-4ac
Δ = -752-4·15·(-315)
Δ = 24525
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24525}=\sqrt{225*109}=\sqrt{225}*\sqrt{109}=15\sqrt{109}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-15\sqrt{109}}{2*15}=\frac{75-15\sqrt{109}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+15\sqrt{109}}{2*15}=\frac{75+15\sqrt{109}}{30} $
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